Announcement

Collapse
No announcement yet.

500 million points for anyone who can solve this maths problem

Collapse
  • Filter
  • Time
  • Show
Clear All
new posts

    #31
    Originally posted by tesla_power View Post
    I dont see the connection between the top and bottom drawing. If that is indeed the case, there is a bit of issue on the problem. Dimensions should be reflected where it is relevant. Unless that bottom drawing is somehow connected to the first ( like a zoom in perhaps ).
    It is connected (It's the same object from different view points) - An engineering orthographic projection drawing.

    Comment


      #32
      Originally posted by miniq View Post
      The calculater just uses all the equations on the main page.

      Work out the Radius and angle Theta job done.



      r = (L.L + 4.X.X)/(8.X) and then,

      theta = 2arcsin(X/2r)

      Area(circle segment) = r.r.(theta - sin(theta))/2
      to work out your input for the circle in the calculator did you do 4.195 - 2.54 = 1.655. Then half that for one circle or leave it as 1.655 to get the calculation for both giving you 11 as the whole area. 9.02 for the rectangle and 1.98 for the 2 arcs?
      Last edited by da_beast; 06-19-2014, 05:37 PM.

      Comment


        #33
        Originally posted by da_beast View Post
        to work out your input for the circle in the calculator did you do 4.195 - 2.54 = 1.655. Then half that for one circle or leave it as 1.655 to get the calculation for both giving you 11 as the whole area. 9.02 for the rectangle and 1.98 for the 2 arcs?
        Use 0.8275 or it messes it all up

        area of 1 arc section= 11 - 9.02 = 1.98 unit^2
        area of 2 arc sections = 1.98 * 2 = 3.96 unit^2

        9.02 + 3.96 = total area.
        Last edited by miniq; 06-19-2014, 05:42 PM.

        Comment


          #34
          are they circles? cOULDDNT YOU JUST USE PIE R squared. Then divide by 2 to gdt half the circles. Then multiply it by 2 to get the full circle.

          Then just work out the rectangle

          Comment


            #35
            Originally posted by da_beast View Post
            I start University in September and currently im just working through past papers to try and get a head start.

            I have completed 12/13 question. However this one is annoying the life out of me.

            [IMG][/IMG]

            if the 2 sides were semi circles i could do it but they arent. Any budding mathematicians on here? I need to find out the area of the shape at the top of the diagram

            [IMG][/IMG]

            This is how i have started.
            I think the question itself might be the problem here. You're not given enough information to calculate the surface area of the oval section... but the question asks 'calculate the area of the sensor'

            However which bit is the sensor? At a guess I'd say it's the pair of probes which project out of of the section - a kinda trick question, at a glance I think you're given enough info to calculate this.

            I have some experience in both answering and setting such questions and think that might be your answer - however I am slightly twisted already - if you want me to calculate the actual valuues for you you'll have to get back to me.

            EDIT - My bad, upon rereading they're obviously looking for an estimate on the area of the oval section - but the information still appears incomplete - you bastard! This f#kkers gonna keep me up half the night now.
            Last edited by Citizen Koba; 06-19-2014, 05:56 PM.

            Comment


              #36
              Originally posted by slimshandy69 View Post
              are they circles? cOULDDNT YOU JUST USE PIE R squared. Then divide by 2 to gdt half the circles. Then multiply it by 2 to get the full circle.

              Then just work out the rectangle
              If they were semi circles you could do this but they are smaller than semi circles

              Comment


                #37
                Originally posted by miniq View Post
                It is connected (It's the same object from different view points) - An engineering orthographic projection drawing.
                Well then that makes sense. It was more than 10yrs since i last saw one. Happy with Fft and dsp now though. Lolz. Come to think of it, drawing looks like an LDR. I take my leave though. Brain cells already fried at work. Cheers. Happy solving.

                Comment


                  #38
                  Originally posted by Koba-Grozny View Post
                  I think the question itself might be the problem here. You're not given enough information to calculate the surface area of the oval section... but the question asks 'calculate the area of the sensor'

                  However which bit is the sensor? At a guess I'd say it's the pair of probes which project out of of the section - a kinda trick question, at a glance I think you're given enough info to calculate this.

                  I have some experience in both answering and setting such questions and think that might be your answer - however I am slightly twisted already - if you want me to calculate the actual valuues for you you'll have to get back to me.
                  I asked my old lecturer and he said the sensor area to be calculated is the whole of the top picture in the diagram.

                  I can do it using the aquarium website but i still dont know how its technically done.

                  Comment


                    #39
                    Originally posted by miniq View Post
                    Use 0.8275 or it messes it all up

                    area of 1 arc section= 11 - 9.02 = 1.98 unit^2
                    area of 2 arc sections = 1.98 * 2 = 3.96 unit^2

                    9.02 + 3.96 = total area.
                    Ah, i think i had right the first time I tried it in the calculator then. I just wasnt sure if that 2.54 was correct because I didn't understand that second picture. I'll see if I can do it on paper when I get home for fun.

                    Comment


                      #40
                      Originally posted by da_beast View Post
                      I asked my old lecturer and he said the sensor area to be calculated is the whole of the top picture in the diagram.

                      I can do it using the aquarium website but i still dont know how its technically done.
                      Yeah... my bad - however you can do it using the sensor seperation 2.54 from the second diagram. This ****'s causing brain overheat - been 20 years since I hadda do this kinda thing.

                      Comment

                      Working...
                      X
                      TOP