500 million points for anyone who can solve this maths problem

[da_beast]

I start University in September and currently im just working through past papers to try and get a head start.

I have completed 12/13 question. However this one is annoying the life out of me.

[IMG][/IMG]

if the 2 sides were semi circles i could do it but they arent. Any budding mathematicians on here? I need to find out the area of the shape at the top of the diagram

[IMG][/IMG]

This is how i have started.

[DoktorSleepless]

This might help. (second problem)

[da_beast]

This might help. (second problem)

Thanks very much. i think i can use that as i know what the equivalent of X is in my diagram.

Such a tricky question.

You want some points?

[Toyman]

Never seen something of this type before..

You just need the surface area of the top figure?

My guess would be to calculate the full area of the rectangle, then estimate the area of each corner triangle (question does say to round angles), and subtract those from the full area of the rectangle,

i would imagine each of the triangles has the same area, but im not familiar with the notation in your example. (e.g - 4.195 +/- 0.25, is the 0.25 the length of the bottom side on each corner, and 4.195 is the length of the main figure?)

if the 0.25 is the length of the corner triangle, then since both length and width have the +/- 0.25, you could asume those are roughly isosceles triangles, and the area of each of those would be (1/32), so you would subtract (4/32) from the main rectngle area.

Assuming i understood the diagram correctly, (and i probaly didn't.), i got 18.9, lol.

[ShoulderRoll]

Nathan Cleverly could solve this.

[miniq]

Engineer here...gimme a moment.

This all the info you've been given?

[da_beast]

Never seen something of this type before..

You just need the surface area of the top figure?

My guess would be to calculate the full area of the rectangle, then estimate the area of each corner triangle (question does say to round angles), and subtract those from the full area of the rectangle,

i would imagine each of the triangles has the same area, but im not familiar with the notation in your example. (e.g - 4.195 +/- 0.25, is the 0.25 the length of the bottom side on each corner, and 4.195 is the length of the main figure?)

if the 0.25 is the length of the corner triangle, then since both length and width have the +/- 0.25, you could asume those are roughly isosceles triangles, and the area of each of those would be (1/32), so you would subtract (4/32) from the main rectngle area.

Assuming i understood the diagram correctly, (and i probaly didn't.), i got 18.9, lol.

Yes just the top figure. the +0.25 is the limit of error and is for another question i have already answered. It isnt relevant to this question.

Im completely stumped.

The base of the triangle i drew is 2.098. Thats half of the width (4.195) so that triangle run from the right hand side to the centre of the diagram.

The 1.775 side is half of the height (3.55).

Again im not even sure if my triangle is correct

[Hewito]

Engineer here...gimme a moment.

This all the info you've been given? if so you can only ever reach an approximate answer...and it's not a good approximation either...

I think the answer is 4

[RINGG]

2.3



``````````

[da_beast]

Engineer here...gimme a moment.

This all the info you've been given? if so you can only ever reach an approximate answer...and it's not a good approximation either...

Thats all i was given. Its driving me mad. In the previous question i had to work out the limits of error but there is nothing in that question relevant for this question.

Because i have the 4.195 width i can calculate the area needed when it asks to calculate it is it was a whole circle.

I just cant figure out how to work out the area of the shape at the top of the diagram. If they were semi circles it would be easy but they arent