500 million points for anyone who can solve this maths problem

[da_beast]

What subject is this? That will proved a clue. Without calculus, this would be a bit hard.

But if i interpret it correctly, that is a square inside a circle.
Thus, calculate the area of the circle using 4.195 as diameter. Then calculate area of the square with 3.55. The difference you divide by 2( as two outer segments are chopped off). Then, just add this to the area of the square.

This is just on top of my head.

Its a rectangle inside the circle measuring 3.55x2.54

[da_beast]

The answer is 12.983 mm^2

The rectanguler section = 9.017 mm^2
The 'circle section' = 1.983 mm^2


Took me way too long...I've given the units of measurement as mm as none were given...

Do you have a formula you used to calculate the area of the circle sections?

[miniq]

Do you have a formula you used to calculate the area of the circle sections?

Aquarium website has everything needed to solve it...and if you're lazy can use the calculator provided on that webpage...looks like you might be using it wrong.

[da_beast]

I think this should be treated as a square inside a problem, the clue is the statement "sensor surface been a complete circle".

Its a rectangle. It asks you to calculate that its a circle because it gives you the diameter the circle would be (4.195).

The rectangle in the middle is 2.54 x 3.55.

This has had me stumped for 2 days. No one i know can answer it. i will upload my previous working that was wrong because i used the wrong triangle 1st time round

[tesla_power]

Its a rectangle inside the circle measuring 3.55x2.54

Sorry is 2.54 given? I dont see it in the original problem.

[miniq]

Sorry is 2.54 given? I dont see it in the original problem.

Bottom of the drawing it's given.

[da_beast]

Sorry is 2.54 given? I dont see it in the original problem.

Yes its right at the bottom of the diagram. the distance between the 2 rods? im assuming thats why the dotted lines on the top picture are shown and why that measurement is given

[da_beast]

Aquarium website has everything needed to solve it...and if you're lazy can use the calculator provided on that webpage...looks like you might be using it wrong.

Yeah that gives me the answer but not the working. I still dont know how to solve the problem lol

[miniq]

Yeah that gives me the answer but not the working. I still dont know how to solve the problem lol

The calculater just uses all the equations on the main page.

Work out the Radius and angle Theta job done.



r = (L.L + 4.X.X)/(8.X) and then,

theta = 2arcsin(X/2r)

Area(circle segment) = r.r.(theta - sin(theta))/2


W = 2.54
L = 3.55
X = 0.8275

[tesla_power]

Bottom of the drawing it's given.

I dont see the connection between the top and bottom drawing. If that is indeed the case, there is a bit of issue on the problem. Dimensions should be reflected where it is relevant. Unless that bottom drawing is somehow connected to the first ( like a zoom in perhaps ).