500 million points for anyone who can solve this maths problem

[Citizen Koba]

That looks correct. However where did you get the figure for the adjacent side? Should it not be 0.8275? Instead of 0.7975?

4.195 - 2.54 = 1.655. That is the depth of the 2 side segments. Half that and it gives us the adjacent side (0.8275?). Half of 3.55 gives us the opposite side

Nah - I think your right - I was half drunk scribbling down the calculations on paper last night and didn't bother to check the results today. (I'm in the middle of moving house and couldn't be bothered looking for a calculator amongst the junk). - Yeah - just looking over my working I read a 1.46 as a 1.40 - musta read the six as zero after subtracting 2.54 from 4 - then added the .195 without noticing.

Also - a heads up - I was in a bit of a hurry before and made a slight mistake - at the second step when I say to subtract theta from 90 to calculate the first angle of your second RA triangle you actually need to subtract theta from it's opposing larger angle (eg - if theta was 20 its opposite would be 70 and the angle you'd produce in your second triangle would be 50). In effect to find the size of the arc at the centre of the circle you need to create an isoceles triangle with it's two equal angles on the perimeter of the circle and it's non-equal side being the Hypoteneuse of the original RA triangle with the dimensions discussed above. Then you need to break the isoceles into 2 **** - the original one discussed, and the second one whose angles and dimensions need calculating. (alternatively you could bisect the isoceles into 2 **** along it's central axis and calculate it's angles and dimensions that way).

Hope that makes sense. Anyways, even if I haven't explained myself terribly well - it looks like you got it beat - you obviously grasp the route to the solution.

K

God help me but I'm rusty as hell - just trying to remember the terminology's giving me a headache - or p'haps that's just the hangover.

[da_beast]

I think i have cracked it. all answers are in scientific notation and in meters instead of millimeters that were displayed on the diagram