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Mosley: Pacquiao will lose; only african americans beat me

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    Mosley: Pacquiao will lose; only african americans beat me

    "Pacquiao is definitely going to lose the fight. He's gonna get beat and the reason why is the only people that I've lost to are African Americans. He's never fought an African American and I've only lost to African Americans. I don't lose to nobody else; everybody else gets smashed. My record shows it," stated three-division world-champion "Sugar" Shane Mosley, who recently returned to his training facilities in Big Bear, California after a cross-country tour to promote his upcoming May 7th showdown with pound-for-pound champion Manny Pacquiao. Enjoying his last days off before starting training camp, Mosley made it clear that he's not at all concerned about any of the skills that the Filipino superstar possesses.

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    #2
    I always knew Cotto was just wayyyy too slick to be Puerto Rican

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      #3
      Mosley's a G.

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        #4








        There goes that theory.

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          #5
          Originally posted by IronDanHamza View Post
          I always knew Cotto was just wayyyy too slick to be Puerto Rican
          African American hair!

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            #6
            mosley been taking to many shots to the head

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              #7
              Cotto's a lightskin spanish-speakin *****.

              He don't count. Duke could pass for Winky Wright's little brother.

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                #8
                Originally posted by IronDanHamza View Post
                I always knew Cotto was just wayyyy too slick to be Puerto Rican
                Cotto's black?

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                  #9
                  Puerto Rican's have African blood in them. And Puerto Rico is part of the United States. Soooooooooooooooooooooooo...

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                    #10
                    Originally posted by Deedubbzz07 View Post
                    Cotto's black?

                    Of course! According to Mosley has only lost to Afircan Americans and Miguel Cotto is just as slick as Zab Judah so he HAS to be black, the theory is flawless.

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